Diagonal Difference

Given a square matrix of size N×N$N\times N$, calculate the absolute difference between the sums of its diagonals.

Input Format

The first line contains a single integer, N$N$. The next N$N$ lines denote the matrix's rows, with each line containing N$N$ space-separated integers describing the columns.

Output Format

Print the absolute difference between the two sums of the matrix's diagonals as a single integer.

Sample Input

3
11 2 4
4 5 6
10 8 -12

Sample Output

15

Explanation

The primary diagonal is: 
11
      5
            -12

Sum across the primary diagonal: 11 + 5 - 12 = 4

The secondary diagonal is:
            4
      5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19 
Difference: |4 - 19| = 15

SOLUTION:

#include <math.h>

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <assert.h>

#include <limits.h>

#include <stdbool.h>

int main(){

    int n,r=0,c=0,i,j,result; 

    scanf("%d",&n);

    int a[n][n];

    for(int a_i = 0; a_i < n; a_i++){

       for(int a_j = 0; a_j < n; a_j++){

          

          scanf("%d",&a[a_i][a_j]);

          

           

       }

    }

    for(i=0;i<n;i++)

        {

         r=r+a[i][i];

    }

    for(i=0,j=n-1;i<n,j>=0;i++,j--)

        { 

        c=c+a[i][j];

    }

    printf("%d",abs(r-c));

    return 0;

}