Python - Problem 1

Question:
Write a program which will find all such numbers which are divisible by 7 but are not a multiple of 5, between 2000 and 3200 (both included).The numbers obtained should be printed in a comma-separated sequence on a single line.Below is the solution code with the explanation.

Code:

l=[]

#starting with loop which will iterate from i1 to i2.Here we are using the Range function available in Python.
for i in range(2000,3201):
    #always becareful with the indent spaces.now we are in the loop.
    ##variable 'i' will be iterated every time and will contain value from 2000 to 3200for every iteration.
    if(i%7==0) and (i%5 != 0):
        #we are appending the satisifed value to the list 'l', but before appending we are converting the value to str for the next usage.
        l.append(str(i))
    #Here we are printing the list.join is used for combining the str values in a list with the specified seperator.
    #in our case the seperator is ',' 
print(','.join(l))
print("total numbers:",len(l))

Output:
     The above code is having hard coded values with a range from 2000 to 3200.Below is the output of the above code.

Let us make some changes to above code so that it will accept different inputs and also with a check that the lower limit value does not exceed higher limit value.
Below is the modified code,

Modified Code:

import time
i1=int(input())
i2=int(input())

start_time = time.time()
l=[]

#starting with loop which will iterate from i1 to i2.Here we are using the Range function available in Python.
if(i1<i2):
    for i in range(i1 ,i2 ):

        #always be careful with the indent spaces.now we are in the loop.
        #variable 'i' will be iterated every time and will contain a value from i1 to i2 for every iteration.

        if(i%7==0) and (i%5 != 0):
            #we are appending the satisifed value to the list 'l', but before appending we are converting the value to str for the next usage.
            l.append(str(i))

    #Here we are printing the list.join is used for combining the str values in a list with the specified seperator.
    #in our case the seperator is ',' 
    print(','.join(l))
    print("total numbers:",len(l))

else:
    print("value 1 should be less than value 2")
print("---seconds---", (time.time() - start_time))

Output:
       The above code will produce the following output.

Python-Printing the list elements on one line with comma separated

                This blog post is about printing the string values present in the list into a single line separated by a comma.

Input: [‘1’,’2’,’3’]

Output: 1, 2, 3

Code:

      #let us take a list with the elements ‘s’,’t’,’r’,’i’,’n’,’g’

      l=[‘s’,’t’,’r’,’i’,’n’,’g’]

      # now this is converted to our required format using the join function and

      # Below is the implementation

      print(‘,’.join(l))

Output:

                s,t,r,i,n,g