Nested Lists-python

Given the names and grades for each student in a Physics class of students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade.
Note: If there are multiple students with the same grade, order their names alphabetically and print each name on a new line.

Input Format

The first line contains an integer, , the number of students.
The subsequent lines describe each student over lines; the first line contains a student's name, and the second line contains their grade.

Output Format

Print the name(s) of any student(s) having the second lowest grade in Physics; if there are multiple students, order their names alphabetically and print each one on a new line.

Sample Input

5
Harry
37.21
Berry
37.21
Tina
37.2
Akriti
41
Harsh
39

Sample Output

Berry
Harry

Explanation

There are students in this class whose names and grades are assembled to build the following list:

students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], 

 ['Harsh', 39]]

The lowest grade of belongs to Tina. The second lowest grade of belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line.

Python 3.0 code:

inputsize=int(input())
students=[[input(),float(input())] for i in range(inputsize)]#for taking the input values
lnew=sorted(list(set([students[i][1] for i in range(inputsize)])),key=float)#for comparing float values
lnew1=sorted([students[i][0] for i in range(inputsize) if lnew[1]==students[i][1]])#list with names having second least score in sorted manner
for i in range(len(lnew1)):
    print(lnew1[i])